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240=x^2
We move all terms to the left:
240-(x^2)=0
We add all the numbers together, and all the variables
-1x^2+240=0
a = -1; b = 0; c = +240;
Δ = b2-4ac
Δ = 02-4·(-1)·240
Δ = 960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{960}=\sqrt{64*15}=\sqrt{64}*\sqrt{15}=8\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{15}}{2*-1}=\frac{0-8\sqrt{15}}{-2} =-\frac{8\sqrt{15}}{-2} =-\frac{4\sqrt{15}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{15}}{2*-1}=\frac{0+8\sqrt{15}}{-2} =\frac{8\sqrt{15}}{-2} =\frac{4\sqrt{15}}{-1} $
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